Mathématiques

Question

comment factoriser :

9(x+1)² -4x

(2x+3)² -(x+1)(2x+3)

2 Réponse

  • 9(x^2+2x+1)-4x
    9x^2+18x+9-4x
    9x^2+14x+9

    4x^2+12x+9 -2(x+1)(2x+3)
    4x^2+12x+9 -(2x+2)(2x+3)
    4x^2+12x+9 -2x(2-3)
    4x^2+12x+9 -2x(-1)
    4x^2+12x+9 -2x
    4x^2+10x+9
  • 9(x+1)² -4x
    9(x+1)
    ² = (3x+3)²
    -4x = -(2
    x)² 
    (3x+3)
    ² - (2x)² 
    (a
    ²-b²) = (a+b)(a-b) (Identité remarquable)
    (3x+3 + 2
    x) (3x+3 -2x)

    (2x+3)² -(x+1)(2x+3)
    (2x+3) (2x+3-x-1)
    (2x+3)(x+2)

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