Mathématiques

Question

Bonjour, pourriez-vous m’aidez à mon dm de maths s’il vous plait
Merci beaucoup !!
Bonjour, pourriez-vous m’aidez à mon dm de maths s’il vous plait Merci beaucoup !!

2 Réponse

  • bonsoir

    i=(9/15+3/10)=
           18/30+9/30=
              27/30=
               9/10
    et 9/10:6/5=
        9/10*5/6=
           45/60=
            3/4

    j =12/7-4/7*35/12
      4/7*35/12=140/84=5/3
    et 12/7-5/3=
         36/21-35/21= 1/21

    k=(4/5+7/10)=
          8/10+7/10=
           15/10=3/2

    (5/6-5/8)=
    20/24-15/24=
      5/24
    et 3/2:5/24=
    3/2*24/5=
    72/10=
    36/5

    l =6/5+21/5:14/15
    21/5:14/15=
    21/5*15/14=
    315/70=
    9/2
     et 6/5+9/2=
           12/10+45/10=
            57/10

    * veut dire multiplier
    : veut dire diviser


  • Bonsoir,
    Voilà,J’ai calculer 3 et Je vous laisse la dernière (même méthode) :)[tex]\frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\[tex] \\ \\ \frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex][tex] \\ \\ \frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex] \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex][tex]\frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex]

    [tex]\frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex][tex] \\ \\ \frac{ \frac{9}{15}+ \frac{3}{10}}{ \frac{6}{5}} = \frac{ \frac{18+9}{30}}{ \frac{6}{5}}= \frac{27}{30} . \frac{5}{6} = \frac{135}{180} = \frac{3}{4} \\ \\ \frac{12}{7} - \frac{4}{7} . \frac{35}{12}= \frac{12}{7} - \frac{140}{84}= \frac{144}{84} - \frac{140}{84} = \frac{4}{84} = \frac{1}{21} \\ \\ \frac{ \frac{4}{5} +\frac{7}{10} }{ \frac{6}{5} -\frac{5}{8} }= \frac{ \frac{15}{10}}{ \frac{23}{40}}= \frac{15}{10} . \frac{40}{23} = \frac{600}{230}= \frac{60}{23} [/tex]