Mathématiques

Question

developper. reduire .ordoner
(x-4)²-(x-1)(x-2)
merci davnce urgen t

2 Réponse

  • (x-4)²-(x-1)(x-2)
    =x²-8x+16-(x²-2x-x+2)
    =x²-8x+16-x²+2x+x-2
    =-5x+14
  • (x-4)² - (x-1)(x-2)= 0
     (x-4)(x-4)-(x²-2x-x+2) = 0
     x²-4x-4x+16-x²+3x-2 = 0
     -5x+14 =0
    -5x = -14
    x=14/5

Autres questions